For chemical leavening: small weight changes alter rise and browning.
1 teaspoon of Vanilla Extract in grams
Reviewed by CupOrGram Editorial TeamData methodology: NIST-derived density references + recipe testing notesMethodology
Answer
4.3 grams
Based on vanilla extract density of 0.88 g/ml
Source: NIST-DB-72
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Need a substitute for Vanilla Extract?
We have 2 tested substitutions with exact ratios.
View substitutions →Quick Reference Table
| teaspoons | grams |
|---|---|
| 1/4 teaspoons | 1.1 grams |
| 1/2 teaspoons | 2.2 grams |
| 1 teaspoons | 4.3 grams |
| 2 teaspoons | 8.7 grams |
| 3 teaspoons | 13.0 grams |
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Density-accurate conversions for baking
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Science Note: Precision within +/-0.002g
Why this conversion matters
Vanilla Extract has a density of 0.88 g/ml, which means it's close to the density of water. Using weight-based measurements gives you consistent results every time.
Recipe Context for Vanilla Extract
For quick breads: over-leavening can cause collapse after oven spring.
For cookies: balance leavening with acid source for predictable spread.
Common Pitfalls
- Switching brands without re-checking weight can change texture and bake time.
- Using volume-only measurements for dense ingredients can overshoot recipe targets.
- Expired leaveners can underperform even when measured correctly.
Brand Variance Example
Baseline on this page: 1 cup vanilla extract = 208g. Real-world range can shift by about 6% because fine powders and leaveners settle during storage, changing cup density.
Example for 2 cups: baseline 416g, common range 392g-440g. If your bake is texture-sensitive, start with the lower bound and adjust after a test batch.